Using a strange or uncommon power tube is a way to make your amp stand out. I am going to take you thru a process to use those uncommon tubes, and today I am going to use a 6146B/8298A. We need to determine if this tube is going to be practical.
Is it practical?
My first stop is https://frank.pocnet.net/sheets/049/6/6146B.pdf. I am looking to see what this tube is used for. I need to know what type of tube this is, plate dissipation in watts, and does it have curve data. Plate dissipation is 27 Watts! It’s a beam power pentode, and curve data is provided.
Decisions
You could play with the parameters to design an awesome power output stage with this calculator https://www.vtadiy.com/loadline-calculators/loadline-calculator/ under 8298A. Use the links at the bottom of this article to design a preamp and match the output transformer.
For those who want to learn how to use plate characteristics (curve data), I will go thru the steps.
Charting the data
The red line above is our do not pass line (plate dissipation). I like to operate at 85% of the 27watt plate dissipation or about 23 watts which could give us a 7-10 watt Single Ended (SE) amp. The red line is 23 watts divided by plate volts to give plate milliampere. Now we just need a load line to find operating voltages, impedance for output transformer, and the value of our bias resistor.
Operating point
The operating point is a red dot in the middle of our purple load line. The operating point is approximately on the -20v grid line, 80 plate milliamperes, and 180 plate volts (just below the curve of the plate dissipation line). to make the purple load line, I simply start at twice the plate milliamperes 160mA. My load line starts at 160mA, crosses thru the red operating point, and ends at 370 plate volts at 0mA. My load line crosses the black cut off line at approximately 155plate milliamperes and 20 plate volts. This means the amp will operate between 0-155mA and 20-370v (350v swing). our impedance is R=V/I (350v/0.155A=2258 Ohms impedance or 2200z). 2200z is close enough and will get us north of 7 watts!
Biasing
We need to know 3 things to bias a power pentode. Grid volts, plate current in amps, and grid #2 current in amps. We know from our operating point that we have -20 grid volts and .08A on the plate. To find the missing grid current we can use the chart above. Line up 180 plate volts from our operating point on the -20 grid volt line and we find 4mA (.004A) on the grid. to find our bias resistor value we just ignore to negative on the 20 grid volts and add plate and grid amps together. Solve V/I=R 20v/(.08A+.004A)=238ohms. The common 220 ohms will be close enough. 220ohm x .084A=18.48v, and now we need to how many watts for our resistor V x I=W (18.48v x .084A=1.6 watts). Use 3-5 watts so the 220 ohm resistor doesn’t overheat.
Hey I have a stereo integrated hifi amp I designed around the 6DQ6B TV sweep tubes, the thing is 40wpc and sounds incredible. I’d be happy to share a pic with you for the post.
Hey I have a stereo integrated hifi amp I designed around the 6DQ6B TV sweep tubes, the thing is 40wpc and sounds incredible. I’d be happy to share a pic with you for the post.
That would awesome! Please feel free to share. I really just want to encourage vacuum tube electronics at all levels.